Determina la masa de:

1.- 2.7mol de HCl
Datos:                                 Formula:
n = 2.7mol                             n = m/PM
m = ?
PM = 36.4g/mol
       ↨
H   1 X 1 = 1
Cl  1 X 35.4 = 35.4
PM = 1 + 35.4 = 36.4g/mol
Despeje:                             Sustitucion:
n = m/PM                           m = (36.4g/mol)(2.7mol))
m = PM (n)
Resultado:
m = 98.28g

2.- 0.325mol de HNO3
Datos:                                Formula:
n = 0.325mol                         n = m/PM
m =?
PM =63g/mol
        ↨
H  1 X 1   =   1
N  1 X 14 = 14
O  3 X 16 = 48
PM = 1 + 14 + 48 = 63g/mol
Despeje:                             Sustitucion:
n = m/PM                           m = (63g/mol)(0.325mol)
m = PM (n)
Resultado:
m = 20.475g

3.-0.75mol de Na2CO3
Datos:                                Formula:
n = 0.75mol                          n = m/PM
m = ?
PM = 106g/mol   
      ↨
Na   2 X 23 = 46
C     1 X 13 = 12
O     3 X 16 = 48
PM = 46 + 12 + 48 = 106g/mol
Despeje:                             Sustitucion:
n = m/PM                           m = (106g/mol)(0.75mol)
m = PM (n)
Resultado:
m = 79.5g